Optimal. Leaf size=73 \[ \frac{2 \sqrt{d+e x} \left (a e^2-b d e+c d^2\right )}{e^3}-\frac{2 (d+e x)^{3/2} (2 c d-b e)}{3 e^3}+\frac{2 c (d+e x)^{5/2}}{5 e^3} \]
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Rubi [A] time = 0.0299421, antiderivative size = 73, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.05, Rules used = {698} \[ \frac{2 \sqrt{d+e x} \left (a e^2-b d e+c d^2\right )}{e^3}-\frac{2 (d+e x)^{3/2} (2 c d-b e)}{3 e^3}+\frac{2 c (d+e x)^{5/2}}{5 e^3} \]
Antiderivative was successfully verified.
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Rule 698
Rubi steps
\begin{align*} \int \frac{a+b x+c x^2}{\sqrt{d+e x}} \, dx &=\int \left (\frac{c d^2-b d e+a e^2}{e^2 \sqrt{d+e x}}+\frac{(-2 c d+b e) \sqrt{d+e x}}{e^2}+\frac{c (d+e x)^{3/2}}{e^2}\right ) \, dx\\ &=\frac{2 \left (c d^2-b d e+a e^2\right ) \sqrt{d+e x}}{e^3}-\frac{2 (2 c d-b e) (d+e x)^{3/2}}{3 e^3}+\frac{2 c (d+e x)^{5/2}}{5 e^3}\\ \end{align*}
Mathematica [A] time = 0.0505959, size = 54, normalized size = 0.74 \[ \frac{2 \sqrt{d+e x} \left (5 e (3 a e-2 b d+b e x)+c \left (8 d^2-4 d e x+3 e^2 x^2\right )\right )}{15 e^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.042, size = 53, normalized size = 0.7 \begin{align*}{\frac{6\,c{e}^{2}{x}^{2}+10\,b{e}^{2}x-8\,cdex+30\,a{e}^{2}-20\,bde+16\,c{d}^{2}}{15\,{e}^{3}}\sqrt{ex+d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.978035, size = 104, normalized size = 1.42 \begin{align*} \frac{2 \,{\left (15 \, \sqrt{e x + d} a + \frac{5 \,{\left ({\left (e x + d\right )}^{\frac{3}{2}} - 3 \, \sqrt{e x + d} d\right )} b}{e} + \frac{{\left (3 \,{\left (e x + d\right )}^{\frac{5}{2}} - 10 \,{\left (e x + d\right )}^{\frac{3}{2}} d + 15 \, \sqrt{e x + d} d^{2}\right )} c}{e^{2}}\right )}}{15 \, e} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.27172, size = 127, normalized size = 1.74 \begin{align*} \frac{2 \,{\left (3 \, c e^{2} x^{2} + 8 \, c d^{2} - 10 \, b d e + 15 \, a e^{2} -{\left (4 \, c d e - 5 \, b e^{2}\right )} x\right )} \sqrt{e x + d}}{15 \, e^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 8.2473, size = 223, normalized size = 3.05 \begin{align*} \begin{cases} - \frac{\frac{2 a d}{\sqrt{d + e x}} + 2 a \left (- \frac{d}{\sqrt{d + e x}} - \sqrt{d + e x}\right ) + \frac{2 b d \left (- \frac{d}{\sqrt{d + e x}} - \sqrt{d + e x}\right )}{e} + \frac{2 b \left (\frac{d^{2}}{\sqrt{d + e x}} + 2 d \sqrt{d + e x} - \frac{\left (d + e x\right )^{\frac{3}{2}}}{3}\right )}{e} + \frac{2 c d \left (\frac{d^{2}}{\sqrt{d + e x}} + 2 d \sqrt{d + e x} - \frac{\left (d + e x\right )^{\frac{3}{2}}}{3}\right )}{e^{2}} + \frac{2 c \left (- \frac{d^{3}}{\sqrt{d + e x}} - 3 d^{2} \sqrt{d + e x} + d \left (d + e x\right )^{\frac{3}{2}} - \frac{\left (d + e x\right )^{\frac{5}{2}}}{5}\right )}{e^{2}}}{e} & \text{for}\: e \neq 0 \\\frac{a x + \frac{b x^{2}}{2} + \frac{c x^{3}}{3}}{\sqrt{d}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.10022, size = 108, normalized size = 1.48 \begin{align*} \frac{2}{15} \,{\left (5 \,{\left ({\left (x e + d\right )}^{\frac{3}{2}} - 3 \, \sqrt{x e + d} d\right )} b e^{\left (-1\right )} +{\left (3 \,{\left (x e + d\right )}^{\frac{5}{2}} - 10 \,{\left (x e + d\right )}^{\frac{3}{2}} d + 15 \, \sqrt{x e + d} d^{2}\right )} c e^{\left (-2\right )} + 15 \, \sqrt{x e + d} a\right )} e^{\left (-1\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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